The angular velocity of particle increases from 0 to omega as it completed x rotations
Answers
Answered by
1
it's angular acceleration is
w^2 = 0^2 + 2a(2π x)
a = w^2 / (4π x)
w^2 = 0^2 + 2a(2π x)
a = w^2 / (4π x)
ask16:
please mark this as brainliest
Similar questions