Question

How many numbers are there between 101 and 999 , which are divisible by both 2 and 3? any champion on the earth to solve it

Answer 1

First no is 102 and second is 108 and last is 996

So by formula of ap

a(n-1)d=996

102(n-1)6=996

6n-6=894

6n=900

N=150

150 terms are there