how many numbers are there from 100 to 200 divisible by 2 or 3
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There will be (200-100)/2+1 = 51 numbers divisible by 2. There will be Floor[(200 - 100)/3] = 33 numbers divisible by 3. Multiples of 6 from the 17th through the 33rd will be counted twice by the sum of these numbers (51+33). There are 17 of them.
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