Question

how many numbers are up to 200, which are divisble by both 2 and 3?
a)23 c)33
b)35 d)29

Answer 1

Answer:

33

Step-by-step explanation:

Clearly this is an arithmetical progression, whose first term is 6 and last term is 198

Hence, First term a=6; common difference d=6; nth term T(n)= 198

We know that, in an arithmetic series

T(n)=a+(n-1)d

198=6+(n-1)6

or, [198–6]/6 = n-1

or, 192/6 = n-1

or, 32 = n-1

or, 32+1 = n

or, n= 33

Thus, there are 33 numbers between 1 and 200 which are divisible by both 2 and 3.

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Answer 2

ANSWERS

Clearly this is an arithmetical progression, whose first term is 6 and last term is 198

Hence, First term a=6; common difference d=6; nth term T(n)= 198

We know that, in an arithmetic series

T(n)=a+(n-1)d

198=6+(n-1)6

or, [198-6]/6 = n-1

or, 192/6 = n-1

or, 32 = n-1

or, 32+1 = n

or, n= 33

ANSWER IS 33