How many numbers between 1 and 1000 are divisible by 3 5 or 7?
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To get the solution of the question you should be familiar with Arithmetic Progression.
Follow the steps and you will get to the answer.
1) The first no. divisible by 5 is 5 and 2nd no. is 10 and so on just keep adding 5 till you reach the last number i.e. 995.
2) So the A.P. is like 5,10,15,20,…,995.
3) Now to find the total number of numbers just put it in the formula.
4) L= a+(n-1)d
5) 995= 5+(n-1)*5
6) n= 199
7) Noe similarly for number divisible by 3 we get he series 3,6,9,12,…….,999
8) From here we get the number of terms
9) n'= 333
10) Now we must take care of repetition that is those numbers which is divided by 3 and 5 both .
11) Those numbers are: 15,30,45,………,990
12) Now total no. of terms from here be n”= 66
13) Therefore total number of terms divisible by 3 or 5 is (n+n'-n”)
14) 199+333–66
15) 466 is the answer.
HOPE IT IS HELPFUL FOR YOU
Follow the steps and you will get to the answer.
1) The first no. divisible by 5 is 5 and 2nd no. is 10 and so on just keep adding 5 till you reach the last number i.e. 995.
2) So the A.P. is like 5,10,15,20,…,995.
3) Now to find the total number of numbers just put it in the formula.
4) L= a+(n-1)d
5) 995= 5+(n-1)*5
6) n= 199
7) Noe similarly for number divisible by 3 we get he series 3,6,9,12,…….,999
8) From here we get the number of terms
9) n'= 333
10) Now we must take care of repetition that is those numbers which is divided by 3 and 5 both .
11) Those numbers are: 15,30,45,………,990
12) Now total no. of terms from here be n”= 66
13) Therefore total number of terms divisible by 3 or 5 is (n+n'-n”)
14) 199+333–66
15) 466 is the answer.
HOPE IT IS HELPFUL FOR YOU
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