Math, asked by Yuvikhorwal, 6 months ago

How many numbers between
100 and 1000 can be formed
with the digit 5,6,7,8,9 if the repetition of digits is not allowed???​

Answers

Answered by ananyaranjan2000
2

Answer: 60

Step-by-step explanation:

Number between 100 and 1000 are 3-digit numbers.

It is given that the digits should not be repeated.

Number of given digits = 5

In a 3-digit number, first number can be arranged in 5 ways.

Second number in 4 ways.

Third number is 3 ways

∴ Numbers that can be formed =5×4×3=60

Answered by tasneemustafa44623
1

Answer:

Using the J programming language:

#a=.10#.5 6 7 8 9{~3 perm 5

60

The answer is 60.

<>>>

List them sorted:

/:~a

567 568 569 576 578 579 586 587 589 596 597 598 657 658 659 675 678 679 685 687 689 695 697 698 756 758 759 765 768 769 785 786 789 795 796 798 856 857 859 865 867 869 875 876 879 895 896 897 956 957 958 965 967 968 975 976 978 985 986 987

Step-by-step explanation:

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