how many numbers between 100 and 600 are divisible by 2 3 and 7
Answers
Answer:
12
Step-by-step explanation:
First we should find out the lcm of the 3 numbers
First we should find out the lcm of the 3 numbersTherefore,2=2 3=3 7=7 and lcm=2*3*7=42
First we should find out the lcm of the 3 numbersTherefore,2=2 3=3 7=7 and lcm=2*3*7=42And we should find out the numbers divisible by 42 between 100 and 600
First we should find out the lcm of the 3 numbersTherefore,2=2 3=3 7=7 and lcm=2*3*7=42And we should find out the numbers divisible by 42 between 100 and 600Ok we can start, we know that 42*2=84 which is below 100 and understood that 42*3 will be more than 100 and it is 126.
First we should find out the lcm of the 3 numbersTherefore,2=2 3=3 7=7 and lcm=2*3*7=42And we should find out the numbers divisible by 42 between 100 and 600Ok we can start, we know that 42*2=84 which is below 100 and understood that 42*3 will be more than 100 and it is 126.so the first number to be divisible is 126.we can consider it as 'a'.OK
First we should find out the lcm of the 3 numbersTherefore,2=2 3=3 7=7 and lcm=2*3*7=42And we should find out the numbers divisible by 42 between 100 and 600Ok we can start, we know that 42*2=84 which is below 100 and understood that 42*3 will be more than 100 and it is 126.so the first number to be divisible is 126.we can consider it as 'a'.OKThen we should find out the last number to be divisible.For that we should divide 600 by 42. So the result will be 14.285......
First we should find out the lcm of the 3 numbersTherefore,2=2 3=3 7=7 and lcm=2*3*7=42And we should find out the numbers divisible by 42 between 100 and 600Ok we can start, we know that 42*2=84 which is below 100 and understood that 42*3 will be more than 100 and it is 126.so the first number to be divisible is 126.we can consider it as 'a'.OKThen we should find out the last number to be divisible.For that we should divide 600 by 42. So the result will be 14.285......We should consider only the '14'.The last number will be 42*14=588 and we can call it 'a@n'
'We should find out more which is the total number divisible by 42.
'We should find out more which is the total number divisible by 42.So,we know that d=42 as it is the divisor.
'We should find out more which is the total number divisible by 42.So,we know that d=42 as it is the divisor.For equations,a@n=a+(n-1)d
'We should find out more which is the total number divisible by 42.So,we know that d=42 as it is the divisor.For equations,a@n=a+(n-1)d 588=126+(n-1)42
'We should find out more which is the total number divisible by 42.So,we know that d=42 as it is the divisor.For equations,a@n=a+(n-1)d 588=126+(n-1)42 (n-1)42=588-126=462
'We should find out more which is the total number divisible by 42.So,we know that d=42 as it is the divisor.For equations,a@n=a+(n-1)d 588=126+(n-1)42 (n-1)42=588-126=462 n-1=462/42=11
'We should find out more which is the total number divisible by 42.So,we know that d=42 as it is the divisor.For equations,a@n=a+(n-1)d 588=126+(n-1)42 (n-1)42=588-126=462 n-1=462/42=11 n=11+1=12
'We should find out more which is the total number divisible by 42.So,we know that d=42 as it is the divisor.For equations,a@n=a+(n-1)d 588=126+(n-1)42 (n-1)42=588-126=462 n-1=462/42=11 n=11+1=12And the answer to the question is found! There are 12 numbers between 100 and 600 which are divisible by 2,3 and 7.