How many numbers between 101 and 300 are divisible by both 3 and 5?
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Hey,
Akarsh roy here(^o^)
.
Here's ur solution
.
To find how many Numbers first of all we have to make a AP which is acc. To the question..........
.
AP formed is....
105,120,135..............285(EXCLUDING 101,300)
.
Here u can observe that every term is divisible by 3 as well as 5.
.
Now, in this AP a=105
d=15
n=?
.
To find no. Of terms a(n) =a+(n-1)d
285 =105+(n-1)15
285=105+15n-15
195/15=n
Therefore NO. of terms between 101 and 300
Is 13
HOPE^o^
Akarsh roy here(^o^)
.
Here's ur solution
.
To find how many Numbers first of all we have to make a AP which is acc. To the question..........
.
AP formed is....
105,120,135..............285(EXCLUDING 101,300)
.
Here u can observe that every term is divisible by 3 as well as 5.
.
Now, in this AP a=105
d=15
n=?
.
To find no. Of terms a(n) =a+(n-1)d
285 =105+(n-1)15
285=105+15n-15
195/15=n
Therefore NO. of terms between 101 and 300
Is 13
HOPE^o^
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