Question

How many numbers between 400 to 700 are divisible by 9 or 11?

Answer 1

the least no divisible by 9 is 405

and the most is 693

hence AP formed is

405,414,423.................................................693

the formula for nth term is given by:

an=a+(n-1)d

so

693=405+(n-1)9

288=(n-1)9

32=n-1

hence , n=33

Answer 2

Thank you for asking this question:

We will assume as the least no divisible by 9 is 405

And the most is 693

So AP will be formed

405,414,423..........................693

The formula for nth term is given by:

an=a+(n-1)d

So, 693=405+(n-1)9

288=(n-1)9

32=n-1

So, n=33

If there is any confusion please leave a comment below.