Math, asked by Sharma8845, 11 months ago

How many numbers divide 2304 and 3888 leaving the same remainder

Answers

Answered by amitnrw
0

30 Numbers Divide   2304 and 3888 leaving the same remainder

Step-by-step explanation:

Lets Say N is the largest number divide 2304  & 3888 leaving same remainder

2304 = AN + r

3888 = BN + r

=> 1584 = (B - A)N

N = 1584  is largest number Which leaves same remainder when divide 2304 and 3888

1584 = 2 * 2 * 2 * 2 * 3 * 3 * 11

= 2⁴ * 3²  * 11¹

(4 + 1)(2 + 1)(1 + 1)

= 5 * 3 * 2 = 30

30 Numbers Divide   2304 and 3888 leaving the same remainder

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