Question

how many numbers in all do we have with:- i- 4digits​

Answer 1

Answer:

8998

Step-by-step explanation:

the first 4digit no. is 1001

and the last is 9999

So a= 1001

d=1

L = 9999

to find no. of terms between 1001 and 9999

n= L - a +1

n = 9999 -1001 +1

n= 8999