how many numbers in between 100 and 1000 which are divisible by 2
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Numbers between 100 and 1000 are 101 and 999 so
first number divisible by 2 is 102 and last is 998 so by A.P.
an = a+(n-1)d
998 = 102 + (n-1) × 2
998 = 102 + (2n-2)
998 - 102 = 2n-2
896 = 2n-2
896+2=2n
898=2n
898/2=n
449=n
So there are 449 numbers between 100 and 1000 which are divisible by 2
first number divisible by 2 is 102 and last is 998 so by A.P.
an = a+(n-1)d
998 = 102 + (n-1) × 2
998 = 102 + (2n-2)
998 - 102 = 2n-2
896 = 2n-2
896+2=2n
898=2n
898/2=n
449=n
So there are 449 numbers between 100 and 1000 which are divisible by 2
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