Math, asked by rajnikantdubey7093, 5 months ago

How many numbers of real roots are present in the given equation
(x + 1)²(x - 5) = 0

Answers

Answered by pradeepdevareddy

0

Answer:

3 roots

Step-by-step explanation:

(x+1)²(x-5) = 0

(x+1)(x+1)(x-5) = 0

x = -1,-1 & 5

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