Question

How many of kilograms of quicklime can be obtained by heating 250 kg of lime stone containing 96% of pure lime stone?
Ans.=134.4 kg

Answer 1

Hello....

CaCO3 -------> CaO + CO2 

Molecular weight of CaCO3

= 40 + 12 + 16(3)

= 100g 

Molecular weight of CaO

= 40 + 16

= 56g 

Amount of limestone available

= (96/100)*250

= 240 g.

When CaCO3 is 100 g. then CaO is 56g.

So, 
when limestone is 250 g then CaO is

(56/100)240 = 134.44 g.

-WonderGirl