how many ordered triplets of integers (a,b,c) are there such that a^3.b.c=24
Answers
Answered by
0
The possible number of such ordered triplets is 2.
We can write 24 in terms of its factors as 2^3.3.1.
Comparing this with the equation given in the question, we know that the value of 'a' can only be 2 whereas 'b' and 'c' can take any of the values in the set {1,3}.
Hence the possible ordered triplets (a,b,c) are (2,3,1) or (2,1,3).
We can write 24 in terms of its factors as 2^3.3.1.
Comparing this with the equation given in the question, we know that the value of 'a' can only be 2 whereas 'b' and 'c' can take any of the values in the set {1,3}.
Hence the possible ordered triplets (a,b,c) are (2,3,1) or (2,1,3).
Similar questions