How many oxygen atoms are present in 54 kg glucose?
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Answer:
molar mass of glucose = 180 g
∴ 54 kg glucose = 54000/180 mole = 30 mole
1 mole glucose(C6H12O6) contain 6 O atom
∴ 30 mole glucose contain 30× 6 O atom = 180 O atom
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The molar mass of glucose can be calculated from the molar masses of individual atoms present in it. From the molecular formula, C6H12O6, one can find there are 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms in one molecule of glucose.
The molar mass of glucose can be calculated from the molar masses of individual atoms present in it. From the molecular formula, C6H12O6, one can find there are 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms in one molecule of glucose.
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