Question

How many Oxygen atoms are present in 96 gram of Ozone ?

Answer 1

Molar mass of Ozone, O3 = 48 g.
Since 48 g of ozone contains 3 oxygen atoms
Thus, 
96 g of ozone will contain 96×348 atoms
= 6 atoms
Hence, 96 g of Ozone contain 6 oxygen atoms.

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Answer 2

Answer: The number of oxygen atoms present in given amount of ozone are $36.132\times 10^{23}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ozone = 96 g

Molar mass of ozone = 48 g/mol

Putting values in above equation, we get:

$\text{Moles of ozone}=\frac{96g}{48g/mol}=2mol$

The chemical formula for ozone is $O_3$.

In 1 mole of ozone molecule, $3\times 6.022\times 10^{23}$ number of oxygen atoms are present.

So, in 2 moles of ozone molecule, $2\times 3\times 6.022\times 10^{23}=36.132\times 10^{23}$ number of oxygen atoms are present.

Hence, the number of oxygen atoms present in the given amount of ozone are $36.132\times 10^{23}$