Question

the molal boiling point constant for water is 0.513 C . when 1 mole of sugar is dissolved in 200g of water the solution boils under a pressure of 1atm at??

Answer 1

Answer:- Solution boils at 102.6 degree C.

Solution:- It's a elevation in boiling point problem solved by using the equation:

$\Delta Tb=i*m*kb$

where, i is Van't hoff factor, m is molality and kb is the molal elevation constant.

Sugar is molecular compound so the value of i for it is 1.

we have 1 mol of sugar dissolved in 200 g that is 0.2 kg of water. So, the molality of the solution = $\frac{1mol}{0.2kg}$

molality of solution = 5m

kb = 0.513

Let's plug in the values in the formula:

$\Delta Tb=1*5*0.513$ = 2.6

Normal boiling point of water is 100 degree C. So, the boiling point of the sugar solution would be = 100 + 2.6 = 102.6 degree C