How many palindromes are there between 4000 and 83000
Answers
>>>790 palindromes are there.
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Answer:
There are 790 palindromes between 4000 and 83000
Explanation:
Since, 4000 < N < 83000, we have to consider various cases for 4-digit numbers and 5-digit numbers
Case 1: for 4-digit numbers
1st digit can be from 4–9 (6 choices)
2nd digit can be from 0–9 (10 choices)
3rd digit must be same as 2nd digit (1 choice)
4th digit must be same as 1st digit (1 choice)
Total 4-digit palindrome numbers > 4000 =6×10×1×1=60
Case 2: 5-digit numbers < 8000
1st digit can be from 1–7 (7 choices)
2nd digit can be from 0–9 (10 choices)
3rd digit can be from 0–9 (10 choices)
4th digit must be same as 2nd digit (1 choice)
5th digit must be same as 1st digit (1 choice)
Total 5-digit palindrome numbers < 80000 =7×10×10×1×1=700
Case 3: 5-digit numbers > 80000 and < 83000
1st digit can be only 8 (1 choice)
2nd digit can be from 0–2 (3 choices)
3rd digit can be from 0–9 (10 choices)
4th digit must be same as 2nd digit (1 choice)
5th digit must be same as 1st digit (1 choice)
Total 5-digit palindrome numbers > 80000 and < 83000 =1×30×10×1×1=30
Total Palindrome numbers N, such that 4000 < N < 83000
=60+700+30
=790