How many permutations r there in a rubiks cube?
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First, we figure out how many arrangements there are, including "simple rotations". There are 3^3=27 blocks to be freely permuted. This means that there are 27! possible arrangements of the blocks (including simple rotations).
Any arrangement can be rotated to yield 24 superficially different arrangements. You can put any of the six faces on the bottom, and then with that face on the bottom, o can rotate it to have any of four faces facing south.
Now, note that any given arrangement can be rotated to yield 24 superfically different arrangements. So, our count of 27! redundantly counts each rotated arrangement 24 times. It follows that our desired total is
27!/24≈4.54×10^26
Happy to help!
Any arrangement can be rotated to yield 24 superficially different arrangements. You can put any of the six faces on the bottom, and then with that face on the bottom, o can rotate it to have any of four faces facing south.
Now, note that any given arrangement can be rotated to yield 24 superfically different arrangements. So, our count of 27! redundantly counts each rotated arrangement 24 times. It follows that our desired total is
27!/24≈4.54×10^26
Happy to help!
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0
d(P,R)=7,
d(P,Q)=10,
d(P,Q)=10,
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