Math, asked by arpitanayak2875, 1 year ago

How many pieces of stone slabs each 24 cm long & 15 cm broad , will be required to lay a path of 18 m long & 12 m wide ?

Answers

Answered by alok7858
1
1st slab 24 cm long & 15 cm broad
24×15 = 360cm (1m =100cm)
=36m
2ed slab 18 m long & 12 m wide
18×12 = 216m
total no of pieces = 2ed slab / 1st slab
=216 / 36 = 6
total no. of pieces = 6
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