Math, asked by reddy2192, 1 year ago

how many pieces of stone slabs,each 24 cm long and 15cm broad will be required to lay a path 18 m long and 12 m wide

Answers

Answered by Anonymous
45
\textsf{Answer :}

6000 slabs will be required.

\textsf{Step-by-step explanation :}

Given,

Length of slab = 24\:cm = 0.24\:m

Breadth of slab = 15\:cm = 01.5\:m

Length of path = 18\:m

Breadth of path = 12\:m

Now, in order to find the piece of stone slabs required to lay the path, we need to find the area of one slab and area of the path. And then divide the area of path by area of one slab.

So, area of slab -

\implies length\times breadth

\implies 0.24\times 0.15

\implies 0.036\:m^{2}

Now, area of path -

\implies length\times breadth

\implies 18\times 12

\implies 216\:m^{2}

Number of slabs required -

\implies \frac{Area\:of\:path}{Area\:of\:slab}

\implies \frac{216}{0.036}

\implies 6000

So, the number of slabs are 6000.

reddy2192: got it thank you
Noah11: Beautifully answered Princess! ^_^
Answered by ITZLOVE
24
Answer -

》Area of slab = 0.24 × 0.15

==> 0.036 m^2

》Area of path = 18 x 12

==> 216 m^2

》Number of slabs = area of path / area of slab

==> 216 / 0.036

==> 6000

Aisha1363: hi
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