Question

How many positive integers less than 100 can be written as the sum of 9 consecutive?

Answer 1

Answer:

7

Step-by-step explanation:

The lowest possible number, less than 100, which is equal to the sum of 9 consecutive positive integers is:

1+2+3+4+5+6+7+8+9 = 45.

The next lowest will be 54.

We know 54 = (45+9),

as we have to increase each number above by 1 (and 9 * 1 = 9).

Thus, 2+3+4+5+6+7+8+9+10 = 54.

Thus we can now write all these numbers which are less than 100, by adding 9 each time to the previous value, to get :--

45 , 54 , 63 , 72 , 81 , 90 , 99 = Total 7 Positive integers.

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Answer 2

Answer:

1+2+3+4+5+6+7+8+9=45

Step-by-step explanation:

the next lowest will be=54