Question

How many pure lines are obtained when LlMmNn x LlMmNn is crossed?

Answer 1

Answer:

Explanation:

Pls find the attachment.

No of gametes produced can be given by the formula.

2^n

Where "n" is no. Of heterozygotes or hybrids.

As in the above question there are 3 heterozygotes.

Hence gametes are 2^3 i.e 8.

Answer 2

Concept Introduction: Mendel started experimenting on Genetics.

Explanation:

We have been Given: LlMmMn × LlMmNn is crossed.

We have to find: How many pure lines are obtained?

Pure Lines are genetically completely Homozygous or Heterozygous.

Since here are 3 alleles governing a property, so the gametes formed will be,

${2}^{3} = 8$

Now, among that 8 gametes, The Number of Pure Lines will be, only 2.

Final Answer: The Number of Pure Lines will be, only 2.

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