How many rectangles can be drawn given that the perimeter of rectangle is 22 and in each case find the area of rectangle. (take length and breadth as whole number)
Answers
Answer:
solved below
Step-by-step explanation:
perimeter p = 22 = 2x + 2y
x + y = 11
( x ,y ) = (1 , 10 ) , area = 10
( x ,y ) = (2 , 9 ) , area = 18
( x ,y ) = (3 , 8 ) , area = 24
( x ,y ) = (4 , 7 ) , area = 28
( x ,y ) = (5 , 6 ) , area = 30
number = 5 rectangles
Step-by-step explanation:
Perimeter of rectangle = 22
2×(length + breadth) = 22
Length + Breadth = 11
So, we have to construct rectangle in which the sum of length and breadth is 11cm.
1+10 = 11
2+9 = 11
3+8 = 11
4+7 = 11
5+6 = 11
Thus, 5 rectangles can be constructed if the perimeter is 22.
We know,
Area of Rectangle = length×breadth
If length = 1, breadth = 10,
area of rectangle = 1 × 10
= 10cm²
If length = 2, Breadth = 9,
area of rectangle = 2×9
= 18cm²
If length = 3, breadth = 8,
area of rectangle = 3×8
= 24cm²
If length = 4, breadth = 7,
area of rectangle = 4×7
= 28cm²
If length = 5, breadth = 6
area of rectangle = 5×6
= 30cm²
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