Question

How many rectangles can be drawn given that the perimeter of rectangle is 22 and in each case find the area of rectangle. (take length and breadth as whole number)​

Answer 1

Answer:

solved below

Step-by-step explanation:

perimeter p = 22 = 2x + 2y

x + y = 11

( x ,y ) = (1 , 10 ) , area = 10

( x ,y ) = (2 , 9 ) , area = 18

( x ,y ) = (3 , 8 ) , area = 24

( x ,y ) = (4 , 7 ) , area = 28

( x ,y ) = (5 , 6 ) , area = 30

number = 5 rectangles

Answer 2

Step-by-step explanation:

Perimeter of rectangle = 22

2×(length + breadth) = 22

Length + Breadth = 11

So, we have to construct rectangle in which the sum of length and breadth is 11cm.

1+10 = 11

2+9 = 11

3+8 = 11

4+7 = 11

5+6 = 11

Thus, 5 rectangles can be constructed if the perimeter is 22.

We know,

Area of Rectangle = length×breadth

If length = 1, breadth = 10,

area of rectangle = 1 × 10

= 10cm²

If length = 2, Breadth = 9,

area of rectangle = 2×9

= 18cm²

If length = 3, breadth = 8,

area of rectangle = 3×8

= 24cm²

If length = 4, breadth = 7,

area of rectangle = 4×7

= 28cm²

If length = 5, breadth = 6

area of rectangle = 5×6

= 30cm²

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