Math, asked by ansh5816, 1 year ago

how many rectangular slabs of 10cm×8cm are required to cover the floor of a hall 12m×10m​

Answers

Answered by Sujalbadgujar
58

Answer:

Step-by-step explanation:

No. Of slbs = (1200×100)/(10×8)

=15000 slabs.

Answered by orangesquirrel
54

Answer: 15000 slabs are required to cover the floor of the hall.

Step-by-step explanation:

Measurements of the floor :

Length= 12 m = 1200 cm

Breadth= 10m = 1000 cm

So area of the floor = length × breadth

= 1200000 cm^2.

Measurements of the rectangular slabs:

Length= 10cm

Breadth = 8 cm

Therefore, area of each slab = 10×8 = 80cm^2

So the number of slabs required to cover the floor = Area of the floor/Area of each slab

= 1200000/80 = 15000 slabs.

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