how many rectangular slabs of 10cm×8cm are required to cover the floor of a hall 12m×10m
Answers
Answered by
58
Answer:
Step-by-step explanation:
No. Of slbs = (1200×100)/(10×8)
=15000 slabs.
Answered by
54
Answer: 15000 slabs are required to cover the floor of the hall.
Step-by-step explanation:
Measurements of the floor :
Length= 12 m = 1200 cm
Breadth= 10m = 1000 cm
So area of the floor = length × breadth
= 1200000 cm^2.
Measurements of the rectangular slabs:
Length= 10cm
Breadth = 8 cm
Therefore, area of each slab = 10×8 = 80cm^2
So the number of slabs required to cover the floor = Area of the floor/Area of each slab
= 1200000/80 = 15000 slabs.
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