how many rectangular tiles 10cm by 7cm will be required to cover a floor 14m by 25/2m and what will be cost at Rs 5 per hundred tiles?
Answers
Answered by
192
In case of floor
Lenght=14m=1400 cm
breadth = 25/2m=1250cm
In case of tile
length = 10cm
breadth = 7cm
no.of tiles required = area of floor/area of tile
=1400×1250/10×7
=25000
so 25000 tiles are required
Lenght=14m=1400 cm
breadth = 25/2m=1250cm
In case of tile
length = 10cm
breadth = 7cm
no.of tiles required = area of floor/area of tile
=1400×1250/10×7
=25000
so 25000 tiles are required
Answered by
33
Given,
The dimensions of the rectangular tiles = 10cm × 7cm
The dimensions of the floor = 14m × 25/2m
Cost of the tiles = Rs. 5 per 100 tiles
To find,
The number of required tiles.
The total cost of the tiles.
Solution,
First of all, we have to calculate the area of a rectangular tile.
Area of the rectangular tile = Length × Breadth = 10×7 = 70 cm²
Now,we have to convert the dimensions of the following into centimetre units.
Length of the floor = 14m = 1400cm
Breadth of the floor = 12.5m = 1250cm
Area of the floor = 1400×1250 = 1750000 cm²
Required number of tiles = 1750000/70 = 25000
Cost of 100 tiles = Rs. 5
Cost of 1 tile = Rs. 5/100
Cost of 25000 tiles = 5×25000/100 = Rs. 1250
Hence, 25000 tiles will be required and total cost will be Rs. 1250
Similar questions
Social Sciences,
8 months ago
Social Sciences,
8 months ago
Math,
8 months ago
Math,
1 year ago
Hindi,
1 year ago
Math,
1 year ago