Math, asked by omesh2715, 1 year ago

how many rectangular tiles 10cm by 7cm will be required to cover a floor 14m by 25/2m and what will be cost at Rs 5 per hundred tiles?

Answers

Answered by Sarth45
192
In case of floor

Lenght=14m=1400 cm

breadth = 25/2m=1250cm

In case of tile

length = 10cm

breadth = 7cm

no.of tiles required = area of floor/area of tile

=1400×1250/10×7

=25000

so 25000 tiles are required
Answered by Anonymous
33

Given,

The dimensions of the rectangular tiles = 10cm × 7cm

The dimensions of the floor = 14m × 25/2m

Cost of the tiles = Rs. 5 per 100 tiles

To find,

The number of required tiles.

The total cost of the tiles.

Solution,

First of all, we have to calculate the area of a rectangular tile.

Area of the rectangular tile = Length × Breadth = 10×7 = 70 cm²

Now,we have to convert the dimensions of the following into centimetre units.

Length of the floor = 14m = 1400cm

Breadth of the floor = 12.5m = 1250cm

Area of the floor = 1400×1250 = 1750000 cm²

Required number of tiles = 1750000/70 = 25000

Cost of 100 tiles = Rs. 5

Cost of 1 tile = Rs. 5/100

Cost of 25000 tiles = 5×25000/100 = Rs. 1250

Hence, 25000 tiles will be required and total cost will be Rs. 1250

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