Question

How many resistors of 55Ω in parallel are required to carry 10A current on a 110V

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Answer 1

Answer:

For x number of resistors of resistance 55 Ω,

Here Supply voltage, V = 110V

Current, I = 10 A

Equivalent resistance of the combination = R, given as

$\frac{1}{R} = x \times \frac{1}{55} \\ \\ R = \frac{55}{x}$

FOR OHMS LAW

$\frac{v}{I } = \frac{55}{x} \\ x = \frac{55 \times I }{v } \\ \\ x = \frac{55 \times 10}{110 } \\ \\ x = 5 \: resistors$

hope it helps u...