how many sides does a polygon of 27 diagnols have? options are: a-12 b-9 c-8 d-7
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n(n-3)/2 = 27
n^2-3=27*2
n^2 = 54/2
n= 18/2= 9
n^2-3=27*2
n^2 = 54/2
n= 18/2= 9
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n(n-1)/2(1) -n = 27. So, n^2 -3n -54 = 0. i.e., n = 9 ignoring the other value -6. Therefore, the polygon which has 27 diagonals has 9 sides.
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