Question

How many silver coins of diameter 5cm and thickness of 4m have 12×11×5cm dimensions?

Answer 1

silver coin is cylindrical in shape

so,

h=4m

r=5/2m

Volume of coin=

$\pi(r ^{2} h)$

22/7×5/2×5/2×4=11/7×5×5×2

=11/7×25×2

=11/7×50

=550/7

=78.57142

=78.57m^3

Volume of rectangle

$lbh$

12×11×5

60×11

660

Total no.=Volume of cuboid/Volume of coin

660/78.57