how many six digit no. in which 6thbplace and 3rd place no. are 4&3 respectively are?
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Step-by-step explanation:
3, 1, 7, 0, 9, 5, i.e. 6 digits.
The total numbers of 6 digit numbers
6! - 5! = 720-120 = 600.
(i) 5! = 120 having 0 at the end.
(ii) Divisible by 5.
They will have zero in the last place and hence the remaining 5 can be arranged in 5! = 120 ways.
They may have 5 in the last place and as above we will have 5! = 120 ways. These' will also include numbers which will have zero in the first place. Therefore the numbers having zero in 1st and 5 in last place will be 4!
Therefore 6 digit numbers having 5 in the end will be
5! -4! = 120 - 2.4 = 96.
Therefore the total number of 6 digit numbers divisible by 5 is
120 + 96 = 216.
(iii) Not divisible by 5.
= Total - (divisible by 5)
=600 - 216 = 384.
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