How many solid sphere of radius of 1 cm will be formed by melting a solid metallic sphere of radius 8cm?
Answers
Answered by
0
Hey
Radius of small sphere ( r ) = 1 cm
Volume of small spheres
= 4 / 3 * pie * ( r ) ³
= 4 / 3 * pie * ( 1 ) ³
= 4 / 3 * pie
Now ,
Radius of larger sphere ( R ) = 8 cm
Volume of larger sphere
= 4 / 3 * pie * ( 8 ) ³
= 4 / 3 * pie * 512
Now ,
number of spheres required
= Volume of larger sphere / volume of smaller sphere
= 4 / 3 * pie * 512 / 4/3 * pie
= 512
thanks :)
Radius of small sphere ( r ) = 1 cm
Volume of small spheres
= 4 / 3 * pie * ( r ) ³
= 4 / 3 * pie * ( 1 ) ³
= 4 / 3 * pie
Now ,
Radius of larger sphere ( R ) = 8 cm
Volume of larger sphere
= 4 / 3 * pie * ( 8 ) ³
= 4 / 3 * pie * 512
Now ,
number of spheres required
= Volume of larger sphere / volume of smaller sphere
= 4 / 3 * pie * 512 / 4/3 * pie
= 512
thanks :)
Answered by
1
Volume of big sphere (V1) = 4/3×pie×r×r×r
= 4/3×pie×8×8×8
= 2048/3 × pie
Volume of small sphere (V2) = 4/3×pie×r×r×r
= 4/3×pie×1×1×1
4/3×pie
No. Of sphere = V1÷V2
= 2048/3×pie ÷ 4/3×pie
= 2048÷4 [ 3 cancels with 3 and pie
cancels with pie]
= 512
Hope it helps.
If you satisfied mark it brainliest.
= 4/3×pie×8×8×8
= 2048/3 × pie
Volume of small sphere (V2) = 4/3×pie×r×r×r
= 4/3×pie×1×1×1
4/3×pie
No. Of sphere = V1÷V2
= 2048/3×pie ÷ 4/3×pie
= 2048÷4 [ 3 cancels with 3 and pie
cancels with pie]
= 512
Hope it helps.
If you satisfied mark it brainliest.
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