Question

How many solutions does the following equation have?
-25z+1+35z=10z+1−25z+1+35z=10z+1

Answer 1

-25z+35z=-1

60z=1

z=1/60=60.

z=60

10z+1-35z

10z+35z=-1

45z=-1

z=1/45=-45

z=-45 ans

10z+1

(10zx1)=10z

60-45+10z

15+10z

z=10/15

z=0.666

or

15+10z

25z

z=25 ans