how many spherical bullets can be made out of a solid cube of lead whose edge measures 44cm, each bullet being 4 cm in diameter
and also the remaining
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Answered by
396
Length of edge of a cube(a) = 44 cm
Volume of the cube = a3 = 44x44x44 = 85184 cm3.
diameter of a spherical bullet = 4 cm
radius of a spherical bullet = 2 cm
volume of the spherical bullet = (4/3)πr3.
V = (4/3) x (22/7) x 2 x 2 x 2 cm3
V = 704 / 21 cm3
let n be the number of bullets.
volume of the n bullets = volume of cube
n x (704 / 21) = 85184 cm3
n = (85184 x 21) / 704
n = 2541 bullets
∴ 2541 spherical solid bullets can be made out of a solid cube
Volume of the cube = a3 = 44x44x44 = 85184 cm3.
diameter of a spherical bullet = 4 cm
radius of a spherical bullet = 2 cm
volume of the spherical bullet = (4/3)πr3.
V = (4/3) x (22/7) x 2 x 2 x 2 cm3
V = 704 / 21 cm3
let n be the number of bullets.
volume of the n bullets = volume of cube
n x (704 / 21) = 85184 cm3
n = (85184 x 21) / 704
n = 2541 bullets
∴ 2541 spherical solid bullets can be made out of a solid cube
Answered by
131
vop. of cube =l^3
=44^3
=85184
vol of one bullet= 4/3πr^3
=4/3×22/7×2^3
=33.52
no of bullet = 85184/33.52
= 2541bullet approx
=44^3
=85184
vol of one bullet= 4/3πr^3
=4/3×22/7×2^3
=33.52
no of bullet = 85184/33.52
= 2541bullet approx
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