Question

How many spherical lead balls of radius 2.1cm can be obtained from a rectangular solid lead with
dimensions 88cm, 42cm and 21cm.​

Answer 1

Given :-

Dimensions of the rectangular solid :-

• Length = 88cm

• breadth = 42cm

• height = 21cm

Therefore it's volume = Length × breadth × height

= 88 × 42 × 21

= 77616cm³

Now, volume of the spherical ball of radius 2.1cm = 4/3πr³

= 4/3 × 22/7 × 2.1 × 2.1 × 2.1

= 88 × 0.7 × 0.3 × 2.1

= 388.08cm³

Hence, total no. of spherical balls can be obtained from the rectangular solid = 77616/388.08

= 200 balls Final answer!

Answer 2

Answer:

Length = 88cm

breadth = 42 cm

height = 21 cm

Formula :

Volume: length × breadth × height

= 88 × 42 × 21

= 77616 cm^ 3

The volume of the spherical ball of radius 2.1 = 4/3pie r

= 4/3 × 22/7 × 2.1 × 2.1× 2.1

=88× 0.7 × 0.3 × 2.1

=388.08 cm^3.

rectangular solid × spherical ball

= 77616 / 388.08

= 200.

Balls = 200.

There are 200 balls.