Question

How many square tiles each of side 20cm are are required to cover the floor of a hall which is 7.2m long and 5.8m wide.​

Answer 1

Given :

• Length of floor = 7.2 m
• Breadth of floor = 5.8 m
• Side of tiles = 20 cm

To Find :

• No. of tiles required = ?

Solution :

~ $\underline{\pmb{\textsf{ Formula \; Used \; :- }}}$

• $\large{\underline{\boxed{\red{\sf{ Area{\small_{(Rectangle)}} = Length \times Breadth }}}}}$

• $\large{\underline{\boxed{\red{\sf{ Area{\small_{(Square)}} = {Side}^{2} }}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ $\underline{\pmb{\textsf{ Calculating \; the \; Area \; of \; Room \; :- }}}$

$\begin{gathered} \; \implies \; \; \sf { Area{\small_{(Room)}} = Length \times Breadth } \\ \end{gathered}$

$\begin{gathered} \; \implies \; \; \sf { Area{\small_{(Room)}} = 7.2 \times 5.8 } \\ \end{gathered}$

$\begin{gathered} \; \implies \; \; {\qquad{\blue{\sf { Area{\small_{(Room)}} = 41.76 \; m² }}}} \\ \end{gathered}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ $\underline{\pmb{\textsf{ Calculating \; the \; Area \; of \; Tiles \; :- }}}$

$\begin{gathered} \; \twoheadrightarrow \; \; \sf { Area{\small_{(Tiles)}} = {Side}^{2} } \\ \end{gathered}$

$\begin{gathered} \; \twoheadrightarrow \; \; \sf { Area{\small_{(Tiles)}} = {20}^{2} } \\ \end{gathered}$

$\begin{gathered} \; \twoheadrightarrow \; \; \sf { Area{\small_{(Tiles)}} = 20 \times 20 } \\ \end{gathered}$

$\begin{gathered} \; \twoheadrightarrow \; \; {\qquad{\orange{\sf { Area{\small_{(Tiles)}} = 400 \; cm² }}}} \\ \end{gathered}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ $\underline{\pmb{\textsf{ Calculating \; No. \; of \; tiles \; Required \; :- }}}$

$\begin{gathered} \; \dashrightarrow \; \; \sf { Tiles \; Required = \dfrac{Area{\small_{(Room)}}}{Area{\small_{(Tiles)}}} } \\ \end{gathered}$

$\begin{gathered} \; \dashrightarrow \; \; \sf { Tiles \; Required = \dfrac{41.76 \; m}{400 \; cm} } \\ \end{gathered}$

$\begin{gathered} \; \dashrightarrow \; \; \sf { Tiles \; Required = \dfrac{41.76 \; m}{400 \; cm} \qquad \; \; \bigg\lgroup{\purple{\sf{ 1 \; m = 100 \; cm }}}\bigg\rgroup } \\ \end{gathered}$

$\begin{gathered} \; \dashrightarrow \; \; \sf { Tiles \; Required = \dfrac{41.76 \times 100}{400} } \\ \end{gathered}$

$\begin{gathered} \; \dashrightarrow \; \; \sf { Tiles \; Required = \dfrac{4176}{400} } \\ \end{gathered}$

$\begin{gathered} \; \dashrightarrow \; \; \sf { Tiles \; Required = \cancel\dfrac{4176}{400} } \\ \end{gathered}$

$\begin{gathered} \; \dashrightarrow \; \; {\qquad{\red{\sf { Tiles \; Required = 10.44 \; Tiles }}}} \\ \end{gathered}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ $\underline{\pmb{\textsf{ Therefore \; :- }}}$

❛❛ Tiles required to tile the room is 10.5 tiles(Approx.) . ❜❜

$\\ {\underline{\rule{300pt}{9pt}}}$