Question

Find the sum of numbers which are divisible by 3 between 10 and 250.​

Answer 1

Answer

Let a be first term & d be the common difference

a=12

d=14

a

n

=248

a

n

=a+(n−1)d

248=12+(n−1)4

⇒248−12=4(n−1)

⇒236=4n−4

⇒240=4n

⇒n=60

∴ There are 60 numbers between 10 & 250 that are divisible by 4.