Question

how many square tiles of side 24 cm will be required to pave the floor of a retangular hall 63m×4.8 m
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Answer 1

Answer:

No.of tiles required = (630 × 480)/24²

= (630 × 20)/24

= 525

Answer 2

$\bf\purple{QuestioN:-}$

How many square tiles of side 24 cm will be required to pave the floor of a rectangular hall 63 m × 4.8 m ??

$\bf\green{AnsweR:-}$

Given :-

Side of the square tile = 24 cm.

Length of the rectangular floor = 63 m.

Breadth of the floor = 4.8 m

To Find :-

No. of tiles required to pave the floor.

Solution :-

The length of the floor is given as 63 m.

The breadth of the floor is given as 4.8 m.

Each side of the square tile = 24 cm.

All the measures are given in different units.

So first we need to convert these into same units.

As we know,

$\huge{\boxed{\bf{\color{\red{\bigstar{1\:metre=100\:cm}}}}}$

Length of the floor

$\longrightarrow\bf{63\:m = 63\times100=6,300\:cm}$

Breadth of the floor

$\longrightarrow\bf{4.8\:m=4.8\times100=480\:cm}$

Therefore,

Area of the floor = length × breadth

⇒ Length × breadth = (6,300 × 480) cm²

⇒ 30,24,000 cm²

Area of the square tile ,

⇒ 24 × 24 cm²

⇒ 576 cm²

[Area of a square = side × side]

∴ No. of tiles required ,

  $\large{\boxed{\bf{\longrightarrow\dfrac{Area\:of\:the\:floor}{Area\:of\:the\:tile}}}}}}}$

   $\large{\boxed{\bf{\longrightarrow\dfrac{30,24,000}{576}}}}}}}$

   $\huge{\boxed{\color{\pink{\bf{\bigstar{5,250\bigstar}}}}}$

Hence, the number of tiles required = 5,250.

All Done !!☺