how many structural isomers of C6 h12 may contain 3 members ring please do it with full solution
I will mark it as brain list
Answers
Answered by
8
one possible six-carbon ring structure: cyclohexane. This structure is drawn by joining the six carbons one to the next in a circle so they form a ring. Draw two hydrogens attached to every carbon.
2
one possible substituted five-carbon ring structure: methylcyclopentane. This structure is drawn by joining five carbons in a ring. Draw the remaining carbon with three hydrogens on it (that is, the "methyl" group CH3-) attached to any one carbon in that ring.
3
four possible substituted four-carbon ring structures: 1,1-dimethylcyclobutane, 1,2-dimethylcyclobutane, 1,3-dimethylcyclobutane and ethylcyclobutane. These structures are drawn by drawing four carbons in a ring. Two CH3- groups are joined to the carbon(s) at the position numbers that appear at the start of the name. Any carbon in the ring can be chosen as No. 1, carbon two would be the one next to it. Continue in that pattern until all four carbons are complete. The exception is ethylcyclobutane, which has the "ethyl" group CH3CH2- attached to any one carbon in the ring.
4
six possible substituted three-carbon ring structures: 1,2,3-trimethylcyclopropane, 1,1,2-trimethylcyclopropane, 1-ethyl-1-methylcyclopropane, 1-ethyl-2-methylcyclopropane, propylcyclopropane and isopropylcyclopropane. These structures are drawn by drawing three carbons in a ring. As before, the appropriate groups are attached at the appropriate carbons as numbered around the ring. A CH3- group is drawn where methyl is found in the name, a CH3CH2- group when ethyl is found, CH3CH2CH2- for propyl and (CH3)2CH2- for isopropyl.
5
four linear four-carbon structures containing one double bond: 2-ethyl-1-butene [CH2=C(CH2CH3)CHCH2CH3], 2,3-dimethyl-2-butene [CH3C(CH3)=C(CH3)CH2CH3], 2,3-dimethyl-1-butene [CH2=C(CH3)CH(CH3)CH3] and 3,3-dimethyl-1-butene [CH2=CHC(CH3)(CH3)CH2CH3].
6
six linear five-carbon structures containing one double bond: 2-methyl-1-pentene [CH2=C(CH3)CH2CH2CH3], 3-methyl-1-pentene [CH2=CHCH(CH3)CH2CH3], 4-methyl-1-pentene [CH2=CHCH2CH(CH3)CH3], 2-methyl-2-pentene [CH3C(CH3)=CHCH2CH3], 3-methyl-2-pentene [CH3CH=C(CH3)CH2CH3] and 4-methyl-2-pentene [CH3CH=CHCH(CH3)CH3].
7
three linear six-carbon structures containing one double bond: 1-hexene [CH2=CHCH2CH2CH2CH3], 2-hexene [CH3CH=CHCH2CH2CH3] and 3-hexene [CH3CH2CH=CHCH2CH3].
2
one possible substituted five-carbon ring structure: methylcyclopentane. This structure is drawn by joining five carbons in a ring. Draw the remaining carbon with three hydrogens on it (that is, the "methyl" group CH3-) attached to any one carbon in that ring.
3
four possible substituted four-carbon ring structures: 1,1-dimethylcyclobutane, 1,2-dimethylcyclobutane, 1,3-dimethylcyclobutane and ethylcyclobutane. These structures are drawn by drawing four carbons in a ring. Two CH3- groups are joined to the carbon(s) at the position numbers that appear at the start of the name. Any carbon in the ring can be chosen as No. 1, carbon two would be the one next to it. Continue in that pattern until all four carbons are complete. The exception is ethylcyclobutane, which has the "ethyl" group CH3CH2- attached to any one carbon in the ring.
4
six possible substituted three-carbon ring structures: 1,2,3-trimethylcyclopropane, 1,1,2-trimethylcyclopropane, 1-ethyl-1-methylcyclopropane, 1-ethyl-2-methylcyclopropane, propylcyclopropane and isopropylcyclopropane. These structures are drawn by drawing three carbons in a ring. As before, the appropriate groups are attached at the appropriate carbons as numbered around the ring. A CH3- group is drawn where methyl is found in the name, a CH3CH2- group when ethyl is found, CH3CH2CH2- for propyl and (CH3)2CH2- for isopropyl.
5
four linear four-carbon structures containing one double bond: 2-ethyl-1-butene [CH2=C(CH2CH3)CHCH2CH3], 2,3-dimethyl-2-butene [CH3C(CH3)=C(CH3)CH2CH3], 2,3-dimethyl-1-butene [CH2=C(CH3)CH(CH3)CH3] and 3,3-dimethyl-1-butene [CH2=CHC(CH3)(CH3)CH2CH3].
6
six linear five-carbon structures containing one double bond: 2-methyl-1-pentene [CH2=C(CH3)CH2CH2CH3], 3-methyl-1-pentene [CH2=CHCH(CH3)CH2CH3], 4-methyl-1-pentene [CH2=CHCH2CH(CH3)CH3], 2-methyl-2-pentene [CH3C(CH3)=CHCH2CH3], 3-methyl-2-pentene [CH3CH=C(CH3)CH2CH3] and 4-methyl-2-pentene [CH3CH=CHCH(CH3)CH3].
7
three linear six-carbon structures containing one double bond: 1-hexene [CH2=CHCH2CH2CH2CH3], 2-hexene [CH3CH=CHCH2CH2CH3] and 3-hexene [CH3CH2CH=CHCH2CH3].
cooldude06:
itna nai pucha tha but thanks bro
Answered by
2
c6h12 has 20 isomers in my senses but if you consider e and z form it is 25
Attachments:
Similar questions