Question

How many term of 1+3+5+7+.........amount to 1234321

Answer 1

Answer:

Step-by-step explanation:

Hence the number of terms  are 1111

Answer 2

The number of terms is 1111

Given,

A series 1+3+5+7+...

To Find,

The number of terms required in the series to get is 1234321.

Solution,

Here, the given series is 1+3+5+7+...

And the first number or term is a = 1.

The common difference value, d is 2.

For a series total amount of the terms is Sₙ.

Sₙ = $\frac{n}{2}$ (2a +(n - 1)d).

Here, the value of Sₙ is 1234321.

And the value of a is 1. and the value of d is 2.

Need to find the value of n, i.e. number of terms.

1234321 = $\frac{n}{2}$ ( 2 * 1 + (n- 1) 2)

1234321 = $\frac{n}{2}$( 2 + (n-1) 2)

1234321 = $\frac{n}{2}$ ( 2n )

$n^{2}$ = 1234321

n = $\sqrt{1234321}$

n = 1111.

Hence, the series required 1111 terms to get the amount of 1234321.

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