How many term of series 1+3+5+7+.... amount to 1234567654321?
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Ans. Is 1,111,111 .Apply the formula of sum of an AP.
Sum = n÷2[2a+(n-1)d]
Where sum =1234567654321,
a = 1 , d = 3-1 = 2
Sum = n÷2[2a+(n-1)d]
Where sum =1234567654321,
a = 1 , d = 3-1 = 2
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