How many term of thw ap 21,18,15 .... Must be added to get the sum 0?
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a=21
d=-3
Given sum =0
so n/2[2a + (n-1)d ]
=>n[42 + (n-1)(-3)]=0
=>42-3-3n =0
=>39 =3n
so n =13
req number of terms is 13
hope it helps
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d=-3
Given sum =0
so n/2[2a + (n-1)d ]
=>n[42 + (n-1)(-3)]=0
=>42-3-3n =0
=>39 =3n
so n =13
req number of terms is 13
hope it helps
plz mark as brainliest
☺☺☺☺☺
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