How many terms are in the sequence of natural numbers between 100 and 300 which leave a remainder 2 on division by 3
Answers
Answered by
3
Answer:
Numbers between 100 and 300 which leave remainder 2 on division by 3 are101 104 107 110 .........299a First number of this sequence = 101b Last number of this sequence = 299d Sum of all numbers in the sequence = n/2a+an∴ Sum of all numbers = 13400
Step-by-step explanation:
Similar questions