how many terms are their in the AP 2,9,16,.....,261?
tahrim89:
I thought 16
Answers
Answered by
4
you can find by formulae= nth term=a+(n-1)d
hope for thsnks
hope for thsnks
Answered by
27
Hello! ! !
Hey my dear friend here is your answer _________
Given sequence of an AP is
2 , 9 , 16 , .......... , 261.
here,
t1 = 2 ; t2 = 9 ; t3 = 16 and tn = 361.
Now,
a = t1 = 3
and
d = t3 - t2 = 9 - 2 = 7
ie. d = 7
we know that;
tn = a + (n - 1)d
261 = 2 + (n - 1)7
261 = 2 + 7n - 7
261 = -5 + 7n
ie. 7n - 5 = 261
7n = 261 + 5
7n = 266
n = 266/7
n = 38
Therefore, there are 38 terms in given AP.
_____________________________
U can take help of pic also....
____________________________
HOPE THIS ANSWER WILL HELP U.....
@Neha...
Hey my dear friend here is your answer _________
Given sequence of an AP is
2 , 9 , 16 , .......... , 261.
here,
t1 = 2 ; t2 = 9 ; t3 = 16 and tn = 361.
Now,
a = t1 = 3
and
d = t3 - t2 = 9 - 2 = 7
ie. d = 7
we know that;
tn = a + (n - 1)d
261 = 2 + (n - 1)7
261 = 2 + 7n - 7
261 = -5 + 7n
ie. 7n - 5 = 261
7n = 261 + 5
7n = 266
n = 266/7
n = 38
Therefore, there are 38 terms in given AP.
_____________________________
U can take help of pic also....
____________________________
HOPE THIS ANSWER WILL HELP U.....
@Neha...
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