Question

How many terms are there in 2, 4, 8, 16, …, 1024?
A) 8
B) 10
C) 15
D) 80​

Answer 1

Answer:

Option A)8 terms

All the above given numbers are in a series following 2 powers

2^1, 2^2, 2^3,...... 2^8.

Answer 2

Step-by-step explanation:

It is a GP. with r = 2, ie

$\begin{aligned} 2^1, 2^2, 2^3... \end{aligned}$

If number of terms is n.

Then,

$\begin{aligned} 2 \times 2^{n-1} = 1024 \end{aligned} \\ =></p><p>\begin{aligned} 2^{n-1} = 512 \end{aligned} \: \\ </p><p>or \: \begin{aligned} 2 \times 2^{n-1} = 2^9 \end{aligned}$

so n-1 = 9 => n = 10