Question

How many terms are there in A.S 1,4,7,10.......2020?

Answer 1

Step-by-step explanation:

The given sequence is an A.P. with first term a=3 and common difference d=3. Let there be n terms in the given sequence. Then,

nth term=111

a+(n−1)d=111

3+(n−1)×3=111

n=37

Thus, the given sequence contains 37 terms.

Answer 2

In this AP

a=1

d=+4

last term=2020

last term=a+(n-1) ×d

where n is total no of terms

2020=1+(n-1)×4

505=1+(n-1)

n=505

so there are 505 terms