how many terms are there in AP :-1 ,-5/6,-2/3,-1/2,............10/3
Answers
Answered by
7
A=-1,.
d=-5/6+1=1/6,
Tn=10/3.
n=?
Tn =a+(n-1)d
10/3= -1+(n-1)1/6
10/3=[-6+n-1]/6
10=[-7+n]/2
10×2=n-7
20+7=n
therefore,, n=27
d=-5/6+1=1/6,
Tn=10/3.
n=?
Tn =a+(n-1)d
10/3= -1+(n-1)1/6
10/3=[-6+n-1]/6
10=[-7+n]/2
10×2=n-7
20+7=n
therefore,, n=27
Answered by
6
We have
A=-1
D=a2-a1=-5/6+1=1/6
Let An=10/3
A+(n-1)d=10/3
-1+(n-1)1/6=10/3
(N-1)/6=13/3
N-1=26
N=27
@skb
A=-1
D=a2-a1=-5/6+1=1/6
Let An=10/3
A+(n-1)d=10/3
-1+(n-1)1/6=10/3
(N-1)/6=13/3
N-1=26
N=27
@skb
Robby16:
its right
Thnx
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