Question

how many terms are there in ap 41,38,35,...,-1​

Answer 1

Step-by-step explanation:

a = 41 , d = -3

An = -1

a + (n-1)d = -1

41 + (n-1)(-3) = -1

41 + 1 = 3(n-1)

3(n-1) = 42

n - 1 = 14

n = 15

There are 15 terms in this arithmetic progression.

Answer 2

Answer:

formula,,,,,,

tn= a+(n-1)d

according to the question..

a=41 ,

tn=-1 & d=-3

then with the help of formula,,,,

-1=41+(n-1) ×3

-42/-3=n-1

14+1=n

n=15,,,,,,,,

but ;;;;

in the term of A.P. series

n is the number of term.

so here number of term is 15 ...

if it helpful for you....

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