Math, asked by ilvupins, 1 year ago

how many terms are there in the sequence 3,6,9,12.....111 Answre

Answers

Answered by veydantnandap879z0
0
unlimited
it goes on
3
6
9
12
15
18
21
...
Please MARK AS THE BRAINLIEST
Answered by asifpasha750gmailcom
1
Hlo...

here we have to use progressions topic..

where. first term,a=3; common difference,d=3;last term,a to base n=1111;n=?..

a to base n=a+(n+1)d
111=3+(n+1)3
111-3=(n+1)3
108/3=n+1
36-1=n
n=35

this is exactly the correct answer ....

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