Question

how many terms in arithmetic sequence 7,14,21,... are between 40 and 28001

Answer 1

Answer:

42,49,56......47993

1 term(a)=42

1 term(a)=42Last term(añ)=47993

Common diffrence=7

añ=a+(n-1)d

47993=42+(n-1)7

47951=(n-1)7

47951/7=n-1

n-1=3773

n=3774

Step-by-step explanation:

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